In eight throws of a die 1 or 3 is considered a success. Then, the standard deviation of success, is

$\frac{16}{9}$ $\frac{8}{3}$ $\frac{4}{3}$ $\frac{2}{3}$

$\frac{4}{3}$

We have, n = 8 and $p=\frac{2}{6}=\frac{1}{3}$ $∴ S.D. = \sqrt{npq}=\sqrt{8×\frac{1}{3}×\frac{2}{3}}=\frac{4}{3}$