A 50 Hz alternating current is flowing in a 28 mH coil. The reactance of the coil is

8.8 Ω

The correct answer is Option (3) → 8.8 Ω

Given:

Frequency: $f = 50 \,\text{Hz}$

Inductance: $L = 28 \,\text{mH} = 28 \times 10^{-3} \,\text{H}$

Formula for inductive reactance:

$X_L = 2 \pi f L$

$X_L = 2 \pi (50)(28 \times 10^{-3})$

$X_L = 2 \pi (1.4)$

$X_L = 8.8 \,\Omega$

Final Answer: $8.8 \,\Omega$