A 50 Hz alternating current is flowing in a 28 mH coil. The reactance of the coil is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 8.8 Ω
Given:
Frequency: $f = 50 \,\text{Hz}$
Inductance: $L = 28 \,\text{mH} = 28 \times 10^{-3} \,\text{H}$
Formula for inductive reactance:
$X_L = 2 \pi f L$
$X_L = 2 \pi (50)(28 \times 10^{-3})$
$X_L = 2 \pi (1.4)$
$X_L = 8.8 \,\Omega$
Final Answer: $8.8 \,\Omega$