Match List-I with List-II
| List-I (Physical Quantity) | List-II (Unit) |
| (A) Magnetic flux | (I) \( \mathrm{T\,m\,A^{-1}} \) |
| (B) Magnetic permeability | (II) \( \mathrm{A\,m^{2}} \) |
| (C) Magnetisation | (III) \( \mathrm{T\,m^{2}} \) |
| (D) Magnetic moment | (IV) \( \mathrm{A\,m^{-1}} \) |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A) - (III), (B) - (I), (C) - (IV), (D) - (II)
Each unit follows from the defining relation of the quantity, with the magnetic field \( B \) in tesla (T).
(A) Magnetic flux — this matches (III) \( \mathrm{T\,m^{2}} \). Flux is field times area.
\( \Phi = BA \;\Rightarrow\; \mathrm{T\,m^{2}}\;(= \mathrm{Wb}) \)
(B) Magnetic permeability — this matches (I) \( \mathrm{T\,m\,A^{-1}} \). From the field inside a solenoid, \( B = \mu n I \), with \( n \) in turns per metre.
\( \displaystyle \mu = \frac{B}{nI} \;\Rightarrow\; \frac{\mathrm{T}}{\mathrm{m^{-1}\,A}} = \mathrm{T\,m\,A^{-1}} \)
(C) Magnetisation — this matches (IV) \( \mathrm{A\,m^{-1}} \). Magnetisation is the magnetic moment per unit volume.
\( \displaystyle M = \frac{m}{V} \;\Rightarrow\; \frac{\mathrm{A\,m^{2}}}{\mathrm{m^{3}}} = \mathrm{A\,m^{-1}} \)
(D) Magnetic moment — this matches (II) \( \mathrm{A\,m^{2}} \). For a current loop the moment is current times area.
\( m = IA \;\Rightarrow\; \mathrm{A\,m^{2}} \)
NCERT (2026-27):
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