Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Time, Speed and Distance

Question:

Speed of a train is 30 percent more than the speed of a car. Both start from point P at the same time and reach point Q at the same time. P and Q are 130 km apart from each other. On the way train stops for 30 minutes at a station. What is the speed of the train?

Options:

78 km/hr

72 km/hr

60 km/hr

70 km/hr

Correct Answer:

78 km/hr

Explanation:

Distance = Speed × Time

Let the speed of the car be x km/hr

According to the question, the Speed of a train is 40% more than the speed of a car. Therefore,

Speed of the train = x × \(\frac{140}{100}\) = \(\frac{7x}{5}\)

Time is taken by car to covered  280 km = \(\frac{280}{x}\)

Since the train stops for 60 minutes, i.e. 1 hr.

Time is taken by Train = \(\frac{280 × 5}{7x}\) + 1    

Since, both time are equal, then

\(\frac{1400}{7x}\) + 1  = \(\frac{280}{x}\)

 \(\frac{200}{x}\) + 1 = \(\frac{280}{x}\)

 200 + x = 280

 x = 80 km/hr

Speed of train =  \(\frac{7x}{5}\) = \(\frac{7 × 80 }{5}\ = 112 km/hr