If $x^4 + \frac{16}{x^4}= 27217, x > 0, $ then the value of $x + \frac{2}{x}$ is :
Answer & explanation
Correct answer: option 4
If x4 + \(\frac{1}{x^4}\) = a
then x2 + \(\frac{1}{x^2}\) = \(\sqrt {a + 2}\) = b
and x + \(\frac{1}{x}\) = \(\sqrt {b + 2}\)
If $x^4 + \frac{16}{x^4}$ = 27217, x > 0,
= x2 + \(\frac{4}{x^2}\) = \(\sqrt {27217 + 2 \times 4}\) = 165
then the value of $x + \frac{2}{x}$ = \(\sqrt {165 + 2 × 2 }\) = 13