As the electron in Bohr orbit of Hydrogen atom passes from state n = 2 to n = 1 , the kinetic energy K and potential energy U change as
Answer & explanation
Correct answer: option 3
U = 2E, K = −E and $E=-\frac{13.6}{n^2}= e V$
$\Rightarrow K_n \propto \frac{1}{n^2}$
And $ U_n \propto \frac{1}{n^2}$
As n changes from n= 2 to n= 1, Both K and U changes 4 fold.