Let f: R-≤ft3/5 → R be defined by f(x)=(3 x+2)/(5 x-3), then

The correct answer is Option (1) → $f^{-1}(x)=f(x)$

$y=\frac{3x+2}{5x-3}⇒5xy-3y=3x+2$

So $5xy-3x=3y+2$

$x=\frac{3y+2}{5y-3}$

So $f^{-1}(x)=\frac{3x+2}{5x-3}$

$⇒f^{-1}(x)=f(x)$