Match List I with List II.
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(A)-(I), (B)-(III), (C)-(II), (D)-(IV) (A)-(IV), (B)-(III), (C)-(II), (D)-(I) (A)-(III), (B)-(II), (C)-(IV), (D)-(I) (A)-(II), (B)-(I), (C)-(III), (D)-(IV) |
(A)-(IV), (B)-(III), (C)-(II), (D)-(I) |
The correct answer is option 2. (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
To match List I (Lattice Point ) with List II (contributions), we need to understand how atoms at different positions within the unit cell contribute to the overall lattice structure. 1. Corner of Cube: An atom at the corner of the cube is shared among 8 unit cells, so its contribution to one unit cell is \(\frac{1}{8}\). 2. Edge of Cube: An atom at the edge of the cube is shared among 4 unit cells, so its contribution to one unit cell is \(\frac{1}{4}\). 3. Face of Cube: An atom on the face of the cube is shared between 2 unit cells, so its contribution to one unit cell is \(\frac{1}{2}\). Given these points: (A) Corner of cube \(\rightarrow\) (IV): A corner atom's contribution of \(\frac{1}{8}\) per unit cell is correct for 8 corners contributing to one atom per unit cell. (B) Edge of cube \(\rightarrow\) (III): An edge atom's contribution of \(\frac{1}{4}\) per unit cell matches with 12 edges contributing to 3 atoms per unit cell (though typically there are 12 edges, each contributing \(\frac{1}{4}\)). (C) Face of cube \(\rightarrow\) (II): A face atom's contribution of \(\frac{1}{2}\) per unit cell matches with 6 faces contributing to 3 atoms per unit cell. (D) Body-centre \(\rightarrow\) (I): A body-centered atom's contribution of 1 is correct as it is wholly within one unit cell. |