The value of van't Hoff factor, $i$, for $CH_3COOH$ solution in water will be

Between 1 and 2

The correct answer is Option (1) → Between 1 and 2

Acetic acid (CH₃COOH) is a weak electrolyte. In water, it partially dissociates into ions:

$\text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}^+$

• If there were no dissociation, $i = 1$
• If there were complete dissociation into two ions, $i = 2$
• Since dissociation is partial, the van’t Hoff factor lies between 1 and 2

 Hence, the correct option is Between 1 and 2.