The area of similar triangle PQR and MNT are 196 cm2 respectively. If the longest side of the larger ΔPQR be 28 cm then what is the length (in cm) of the longest side of the smaller ΔMNT?

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26

From the similarity theorem we have a concept, =  \(\frac{ PR^2}{ MT^2}\) = \(\frac{arPQR}{arMNT }\) = \(\frac{28}{MT}\) = \(\frac{14}{13}\) = MT = 26 cm