If A is a m × n matrix and B is n × p matrix and m ≠ p then, |
$(AB)^T= B^TA^T$ (BA)'= A'B' (AB)' = A'B' (BA)' = B'A' |
$(AB)^T= B^TA^T$ |
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Given $A$ is an $m\times n$ matrix and $B$ is an $n\times p$ matrix. The product $AB$ is defined and is of order $m\times p$. Property of transpose: $(AB)^T = B^T A^T$ always holds, irrespective of $m\neq p$. Check options: Option 1: $(AB)^T = B^T A^T$ → correct. Option 2: $(BA)' = A'B'$ → $BA$ may not even be defined, so incorrect. Option 3: $(AB)' = A'B'$ → incorrect order. Option 4: $(BA)' = B'A'$ → $BA$ may not be defined. final answer: Option 1 |