Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Indefinite Integration

Question:

\(\frac{(1-\cos x)^{\frac{2}{7}}}{(1+\cos x)^{\frac{9}{7}}} dx\) is

Options:

\(\frac{4}{7}\left(\tan \frac{x}{2}\right)^{-\frac{3}{7}}+c\)

\(\frac{7}{11}\left(\tan \frac{x}{2}\right)^{\frac{11}{7}}+c\)

\(\frac{7}{11}\left(\cos \frac{x}{2}\right)^{\frac{11}{7}}+c\)

\(\frac{4}{7}\left(\sin \frac{x}{2}\right)^{-\frac{3}{7}}+c\)

Correct Answer:

\(\frac{7}{11}\left(\tan \frac{x}{2}\right)^{\frac{11}{7}}+c\)

Explanation:

\(\begin{aligned}\int \frac{(1-cos x)^{\frac{2}{7}}}{(1+\cos x)^{\frac{9}{7}}}dx&=\frac{1}{2}\int \frac{\left(\sin \frac{x}{2}\right)^{\frac{4}{7}}}{\left(\cos \frac{x}{2}\right)^{\frac{18}{7}}}dx\\&=\frac{1}{2}\int \left(\tan \frac{x}{2}\right)^{\frac{4}{7}}\sec^{2} \frac{x}{2} dx\\ &=\frac{1}{2} \int 2t^{\frac{4}{7}}dt\\ &=\frac{7}{11}\left(\tan \frac{x}{2}\right)^{\frac{11}{7}}+c\end{aligned}\)