A circle inscribed in a triangle ABC touches its sides AB, BC and AC at the points D, E and F, respectively. If AB = 18 cm, BC = 15 cm and AC = 13 cm, then the value of AD + BE + CF is:
Answer & explanation
Correct answer: option 3
We have,
AB = 18
BC = 15
AC = 13
We know,
AD = AF, DB = BE, CE = FC
The perimeter of the triangle = 18 + 15 + 13 = 46
= AD + AF + BD + BE + CE + CF = 46
= 2 × (AD + BE + CF) = 46
= (AD + BE + CF) = 23 cm