Number B is 17.5% less than number A, while number C is 22.5% more than number B. If the value of C is given as 8085, what is the value of A?

8000

Let value of B = 100x 

value of Number C = 100x + 22.5% of 100x = 122.5x

122.5x = 8085

x = 66

100x = 6600 (value of B )

Let value of A = 100y

Value of B = 100y - 17.5% of 100y = \(\frac{82.5y}{100}\)

\(\frac{82.5y}{100}\) = 6600

y = 80

100y = 8000

Value of A = 8000