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CUET
General Test
Quantitative Reasoning
Geometry
If AD is an altitude of an isosceles triangle ABC in which AB = AC. Then:
BD=CD
BD>CD
BD<CD
None of the above
In ΔABD and ΔACD, ∠ADB = ∠ADC = 90° AB = AC (Given) AD = AD (Common) ∴ ΔABD ≅ ΔACD (By RHS congruence condition) BD = CD
We can also use AAS criteria as ∠ABD and ∠ACD are equal (Sides AB and AC are equal)