The cartesian equation of plane whose intercept on the coordinate axes are 2, -3 and 4 is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $6x-4y+3z=12$
Eq: $\frac{x}{2}+\frac{y}{-3}+\frac{z}{4}=1$
$6x-4y+3z=12$
The cartesian equation of plane whose intercept on the coordinate axes are 2, -3 and 4 is :
Correct answer: option 1
The correct answer is Option (1) → $6x-4y+3z=12$
Eq: $\frac{x}{2}+\frac{y}{-3}+\frac{z}{4}=1$
$6x-4y+3z=12$