The cartesian equation of plane whose intercept on the coordinate axes are 2, -3 and 4 is :

$6x-4y+3z=12$ $4x-6y+3z=12$ $6x+3y-4z=12$ $6x+3y+4z=12$

$6x-4y+3z=12$

The correct answer is Option (1) → $6x-4y+3z=12$ Eq: $\frac{x}{2}+\frac{y}{-3}+\frac{z}{4}=1$ $6x-4y+3z=12$