If velocity of a galaxy relative to earth is $1.2 × 106 ms^{–2}$ then % increase in wavelength of light from galaxy as compared to the similar source on earth will be |
0.3 % 0.4 % 0.5 % 0.6 % |
0.4 % |
Since $\frac{v}{c}=\frac{Δλ}{λ}$ $∴Δλ=\frac{v}{c}xλ$ or $\frac{Δλ}{λ}=\frac{1.2×10^6}{3×10^8}=\frac{12}{3}×\frac{10^5}{10^8}=4×10^{-3}$ $\frac{Δλ}{λ}×100=0.4$ i.e., 0.4% |