CUET Preparation Today
The interval in which the function f given by f(x) = x2 - 4x + 6 is strictly increasing is |
(-∞, 2) (-∞,-2) (2,∞) (-2,∞) |
(2,∞) |
f(x) = x2 - 4x + 6 (x) = 2x - 4 f'(x) = 0 gives us 2x - 4 = 0 or x = 2 point x = 2 divides the real line into two disjoint intervals (-∞, 2)(2, ∞) So interval (2, ∞), f'(x) > 0 ∴ f is strictly increasing in (2, ∞) |
