The interval in which the function f given by f(x) = x2 - 4x + 6 is strictly increasing is
Answer & explanation
Correct answer: option 3
f(x) = x2 - 4x + 6
(x) = 2x - 4
f'(x) = 0 gives us 2x - 4 = 0 or x = 2
point x = 2 divides the real line into two disjoint intervals (-∞, 2)(2, ∞)
So interval (2, ∞), f'(x) > 0
∴ f is strictly increasing in (2, ∞)