Match List-I with List-II
| List-I | List-II | ||
| A. | The solution set of the inequality $3x+7 > 12 $ | I. | $[-1, ∞]$ |
| B. | The solution set of the inequality $\frac{3x+5}{2}≥1, x \in R$ | II. | $[\frac{17}{18}, ∞]$ |
| C. | The solution set of the inequality $2x+5 < 7x + 9, x \in R $ is, | III. | $(\frac{5}{3}, ∞)$ |
| D. | The solution set of the inequality $6x-5≥-2x+12, x \in R $ is, | IV. | $(-\frac{4}{5}, ∞)$ |
Choose the correct answer from the options given below :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → A-III, B-I, C-IV, D-II
(A) $3x+7>12$
$⇒3x>5$
$⇒x>\frac{5}{3}⇒x∈\left(\frac{5}{3}, ∞\right)$ → (III)
(B) $\frac{3x+5}{2}≥1$
$⇒3x+5≥2$
$⇒3x≥-3$
$⇒x≥-1⇒x∈[-1,∞)$ → (I)
(C) $2x+5<7x+9$
$⇒5x>-4$
$⇒x>-\frac{4}{5}⇒x∈\left(\frac{-4}{5}, ∞\right)$ → (IV)
(D) $6x-5≥-2x+12$
$8x≥17$
$x≥\frac{17}{8}⇒x∈\left(\frac{17}{8}, ∞\right)$ → (II)