The correct answer is option 4. A(IV), B(III), C(II), D(I).
Let us go into the details of each oxide of nitrogen and their proper methods of preparation:
A. \(N_2O\):
Proper Method of Preparation (IV): Prepared by heating ammonium nitrate.
The reaction involved is: \( NH_4NO_3 \rightarrow N_2O + 2H_2O \)
Ammonium nitrate (\(NH_4NO_3\)) decomposes upon heating to produce \(N_2O\) and water.
B. \(N_2O_3\):
Proper Method of Preparation (III): Blue solid.
\(N_2O_3\) is a blue solid, and its preparation method is not explicitly mentioned. However, it is known to exist as a dimer equilibrium with \(N_4O_6\) and is formed by the reaction of \(NO\) with \(NO_2\).
C. \(NO_2\):
Proper Method of Preparation (II): Dimerizes easily.
\(NO_2\) is known to dimerize easily to form \(N_2O_4\), especially at lower temperatures. The dimerization is represented as \(2NO_2 \rightarrow N_2O_4\).
D. \(NO\):
Proper Method of Preparation (I): Prepared from sodium nitrite.
The reaction involved is: \(2NaNO_2 + 2H_2SO_4 \rightarrow 2NO + 2NaHSO_4 + H_2O\)
Sodium nitrite (\(NaNO_2\)) reacts with sulfuric acid (\(H_2SO_4\)) to produce \(NO\), sodium hydrogen sulfate (\(NaHSO_4\)), and water.
In summary, the matching of the oxides of nitrogen with their proper methods of preparation based on the given information is:
A. \(N_2O\) (IV): Prepared by heating ammonium nitrate.
B. \(N_2O_3\) (III): Blue solid.
C. \(NO_2\) (II): Dimerizes easily.
D. \(NO\) (I): Prepared from sodium nitrite.
So, the correct match is (D) A(IV), B(III), C(II), D(I). |
