Match List I with List II List I (Oxides of nitrogen) List II (Proper…

The correct answer is option 4. A(IV), B(III), C(II), D(I).

Let us go into the details of each oxide of nitrogen and their proper methods of preparation:

A. \(N_2O\):
Proper Method of Preparation (IV):  Prepared by heating ammonium nitrate.
The reaction involved is: \( NH_4NO_3 \rightarrow N_2O + 2H_2O \)
Ammonium nitrate (\(NH_4NO_3\)) decomposes upon heating to produce \(N_2O\) and water.

B. \(N_2O_3\):
Proper Method of Preparation (III): Blue solid.
\(N_2O_3\) is a blue solid, and its preparation method is not explicitly mentioned. However, it is known to exist as a dimer equilibrium with \(N_4O_6\) and is formed by the reaction of \(NO\) with \(NO_2\).

C. \(NO_2\):
Proper Method of Preparation (II): Dimerizes easily.
\(NO_2\) is known to dimerize easily to form \(N_2O_4\), especially at lower temperatures. The dimerization is represented as \(2NO_2 \rightarrow N_2O_4\).

D. \(NO\):
Proper Method of Preparation (I): Prepared from sodium nitrite.
The reaction involved is: \(2NaNO_2 + 2H_2SO_4 \rightarrow 2NO + 2NaHSO_4 + H_2O\)
Sodium nitrite (\(NaNO_2\)) reacts with sulfuric acid (\(H_2SO_4\)) to produce \(NO\), sodium hydrogen sulfate (\(NaHSO_4\)), and water.

In summary, the matching of the oxides of nitrogen with their proper methods of preparation based on the given information is:
A. \(N_2O\) (IV): Prepared by heating ammonium nitrate.
B. \(N_2O_3\) (III): Blue solid.
C. \(NO_2\) (II): Dimerizes easily.
D. \(NO\) (I): Prepared from sodium nitrite.

So, the correct match is (D) A(IV), B(III), C(II), D(I).