Match List I with List II
| List I (Oxides of nitrogen) | List II (Proper method of preparation) |
| (A) N2O | (I) Prepared from sodium nitrite |
| (B) N2O3 | (II) Dimerises easily |
| (C) NO2 | (III) Blue solid |
| (D) NO | (IV) Prepared by heating ammonium nitrate |
Choose the correct answer from the options given below :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → A(IV), B(III), C(II), D(I)
(A) \( \ce{N2O} \) — This matches (IV) Prepared by heating ammonium nitrate.
\( \displaystyle \ce{NH4NO3} \xrightarrow{\text{heat}} \ce{N2O + 2H2O} \)
(B) \( \ce{N2O3} \) — This matches (III) Blue solid. Dinitrogen trioxide is a blue solid (acidic).
(C) \( \ce{NO2} \) — This matches (II) Dimerises easily. \( \ce{NO2} \) has an odd number of valence electrons; two molecules pair up to give the stable \( \ce{N2O4} \).
\( \displaystyle \ce{2NO2 <=> N2O4} \)
(D) NO — This matches (I) Prepared from sodium nitrite.
\( \displaystyle \ce{2NaNO2 + 2FeSO4 + 3H2SO4 -> Fe2(SO4)3 + 2NaHSO4 + 2H2O + 2NO} \)
Note: This question is from the pre-rationalised NCERT book (2022-23). The topic is not there in the latest NCERT book (2026-27), and it is also out of the CUET 2026 syllabus.
NCERT (Pre-rationalised edition, 2022-23):
Oxides of Nitrogen – …
