If tanA = \(\frac{3}{7.2}\),  find the value of 65 cosA + 26 tanA.

70 60 90 100

70

tanA = \(\frac{3}{7.2}\) = \(\frac{30}{72}\) = \(\frac{5}{12}\) = \(\frac{P}{B}\)   [Triplet 5, 12, 13] H = 13×0.6 = 7.8 Now, cosA = \(\frac{B}{H}\), then 65 cosA + 26 tanA = 65 × \(\frac{7.2}{7.8}\) + 26 × \(\frac{3}{7.8}\) = 60 + 10 = 70