Statement I: \([Co(NH_3)_3Cl_3]\)does not give a white precipitate with AgNO3 solution
Statement II: Chlorine is not present in the ionizing sphere
Answer & explanation
Correct answer: option 1
The correct answer is: 1. Both Statement I and Statement II are correct, and Statement II is the correct explanation of Statement I.
Statement I: \([Co(NH_3)_3Cl_3]\) does not give a white precipitate with \(AgNO_3\) solution.
Statement II: Chlorine is not present in the ionizing sphere.
Both statements are correct:
Statement I is true. \([Co(NH_3)_3Cl_3]\) does not give a white precipitate with AgNO3 solution because all three chloride ions \((Cl^-)\) are already coordinated with the cobalt ion in the complex. As a result, there are no free chloride ions available to react with \(AgNO_3\) and form a white precipitate.
Statement II is also true. The ionizing sphere of a coordination complex includes the central metal ion and the ligands directly coordinated to it. In the case of \([Co(NH_3)_3Cl_3]\), the ionizing sphere consists of the cobalt ion and the three ammonia ligands \((NH_3)\). The chloride ions \((Cl^-)\) are part of the coordination sphere and are not included in the ionizing sphere.
Statement II provides the correct explanation for why \([Co(NH_3)_3Cl_3]\) does not give a white precipitate with \(AgNO_3\). Since chlorine is not present in the ionizing sphere, it means that all three chloride ions are coordinated with the cobalt ion, leaving no free chloride ions available to react with \(AgNO_3\).