Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Options:

a

b

c

d

Correct Answer:

a

Explanation:

Linear Charge density $\lambda = \frac{q}{l} = \frac{5 \times 10^{-10}}{10} = 5\times 10^{-11} C/m$

Electric field $E = \frac{\lambda}{2\pi\epsilon_0 r} = 4.5 V/m$