Answer & explanation
Correct answer: option 1
Linear Charge density $\lambda = \frac{q}{l} = \frac{5 \times 10^{-10}}{10} = 5\times 10^{-11} C/m$
Electric field $E = \frac{\lambda}{2\pi\epsilon_0 r} = 4.5 V/m$
Correct answer: option 1
Linear Charge density $\lambda = \frac{q}{l} = \frac{5 \times 10^{-10}}{10} = 5\times 10^{-11} C/m$
Electric field $E = \frac{\lambda}{2\pi\epsilon_0 r} = 4.5 V/m$