Practicing Success
The domain of definition of the function y(x) given by the equation $2^x + 2^y = 2$ is : |
$0<x \leq 1$ $0 \leq x \leq 1$ $-\infty<x \leq 0$ $-\infty<x<1$ |
$-\infty<x<1$ |
$2^x + 2^y = 2$ $⇒ y = \log_2(2 -2^x)$ So, $2 – 2^x>0 ⇒ x < 1$ $⇒x∈(-∞,1)$ Hence (4) is the correct answer. |