The total revenue function R(x) (in rupees) for selling x number of units of a commodity is given by
\(R(x)=3x^2+600\)
The least number of units of the commodity to be sold to attain minimum marginal revenue of Rs. 120 is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 20
The marginal revenue is the derivative of the total revenue:
\( \displaystyle MR = \frac{dR}{dx} = 6x \)
A marginal revenue of at least Rs. 120 needs
\(6x \ge 120\)
\(x \ge 20\)
So the least number of units is 20.