The total revenue function R(x), (in rupees) for selling x number of units of a commodity is given by
$R(x)=(3x^2+600)$
The least number of units of the commodity to be sold to attain minimum marginal revenue pf ₹120 is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 20
$MR(x)=R'(x)$
$R'(x)=\frac{d}{dx}(3x^2+600)$
$=6x$
$120=6x$
$x=20$