CUET Preparation Today
The total revenue function R(x), (in rupees) for selling x number of units of a commodity is given by $R(x)=(3x^2+600)$ The least number of units of the commodity to be sold to attain minimum marginal revenue pf ₹120 is : |
10 20 30 40 |
20 |
The correct answer is Option (2) → 20 $MR(x)=R'(x)$ $R'(x)=\frac{d}{dx}(3x^2+600)$ $=6x$ $120=6x$ $x=20$ |
