Practicing Success
Practicing Success
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In the formula $X = 3 YZ^2$, X and Z have dimensions of capacitance and magnetic induction respectively. The dimensions of Y in MKSA system are : |
$[M^{–3}L^{–2}T^{–2}A^{–4}]$ $[ML^{–2}]$ $[M^{–3}L^{–2}A^4T^8]$ $[M^{–3}L^2A^4T^4]$ |
$[M^{–3}L^{–2}A^4T^8]$ |
The correct answer is Option (3) → $[M^{–3}L^{–2}A^4T^8]$ $Dimensions\, of\, Y = \frac{dimensions\, of\, X}{dimensions\, of\, Z^2}$ $=\frac{M^{-1}L^{-2}T^4A^2}{(MT^{-2}A^{-2})^2}$ $=[M^{–3}L^{–2}T^8A^4]$ |
