In the formula $X = 3 YZ^2$, X and Z have dimensions of capacitance and magnetic induction respectively. The dimensions of Y in MKSA system are :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $[M^{–3}L^{–2}A^4T^8]$
$Dimensions\, of\, Y = \frac{dimensions\, of\, X}{dimensions\, of\, Z^2}$
$=\frac{M^{-1}L^{-2}T^4A^2}{(MT^{-2}A^{-2})^2}$
$=[M^{–3}L^{–2}T^8A^4]$