Mahesh, Suresh and Raju together can complete a work in 18 days. Mahesh and Suresh together can complete the same work in 72 days. Raju alone can finish the same work in how many days?
Answer & explanation
Correct answer: option 2
Total Work = LCM of 18, 72 = 72
'
Efficiency of Raju = eff(Mahesh+Suresh+Raju) - eff(Mahesh+Suresh)
= 4 - 1 = 3
Time taken by Raju alone to complete the work = $\frac{total\;work}{efficiency\;of\;Raju}$
= $\frac{72}{3}$ = 24 days