If x2 - 44x + 1= 0
and x > 1, then the value of
x2 + \(\frac{1}{x^2}\) will be:
Answer & explanation
Correct answer: option 1
If x2 - 44x + 1= 0
Divide by x on both sides,
x + \(\frac{1}{x}\) = 44
x2 + \(\frac{1}{x^2}\) = 442 - 2 = 1934
⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2