Two people A and B are at a distance of 220 km from each other at 10: 30 Am. After 30 minutes. A starts moving towards B at a speed of 40 km/hr while at 12 PM, B starts moving away from A at a speed of 30 km/hr. At what time will they meet on the next day?
Answer & explanation
Correct answer: option 4
A starts running at 11:00 pm
Distance = Speed × Time
So , Distance traveled by A in 1 hour from 11:00 pm to 12:00 pm = 40 × 1
= 40 km
Remaining distance = 220 - 40 = 180 km
Relative speed = 40 - 30 = 10 km/h
( when moves in same direction )
Time taken = \(\frac{Distance }{Speed}\)
= \(\frac{180 }{10}\)
= 18 hours
So , They will meet = 12:00 pm + 18 hours = 6:00 AM