CUET Preparation Today
Differentiation of log x w.r.t $\frac{1}{x}$ is : |
$-\frac{1}{x^3}$ $-\frac{1}{x}$ $-x$ $\frac{1}{x}$ |
$-x$ |
The correct answer is Option (3) → $-x$ $\frac{d(\log x)}{dz}=\frac{1}{x}\frac{dx}{dz}$ $\frac{d(\frac{1}{x})}{dz}=-\frac{1}{x^2}\frac{dx}{dz}$ $∴\frac{d(\log x)}{d(\frac{1}{-x})}=\frac{\frac{1}{x}}{\frac{1}{x^2}}=\frac{-x^2}{x}=-x$ |
