A domestic appliance draws 2.5 A from a 220 V, 50 Hz power supply. The amplitude of current is |
3.5 A 2.5 A 1.8 A 0 A |
3.5 A |
The correct answer is Option (1) → 3.5 A Given: RMS current: $I_{\text{rms}} = 2.5\ \text{A}$ Amplitude (maximum) current: $I_0 = \sqrt{2} I_{\text{rms}} = \sqrt{2} \cdot 2.5 \approx 3.54\ \text{A}$ Amplitude of current $≈ 3.54$ A |