Match List – I with List – II.

Choose the correct answer from the options given below:

A - III, B - I, C - IV, D - II

The correct answer is Option (1) → A - III, B - I, C - IV, D - II

$\text{(A)}\; (1129+937)\mod 11$

$1129\equiv 7,\;\; 937\equiv 2 \Rightarrow 7+2=9 \Rightarrow \text{(III)}$

$\text{(B)}\; (1129-937)\mod 11$

$7-2=5 \Rightarrow \text{(I)}$

$\text{(C)}\; (1129\times 937)\mod 11$

$7\times 2=14\equiv 3 \Rightarrow \text{(IV)}$

$\text{(D)}\; \text{Last digit of } (12)^{12}$

$2^{12}\Rightarrow \text{cycle } 2,4,8,6 \Rightarrow 12\mod 4=0 \Rightarrow 6 \Rightarrow \text{(II)}$

A–III,\; B–I,\; C–IV,\; D–II