Match List – I with List – II.
|
LIST I |
LIST II |
|
A. The value of (1129 + 937)(mod 11) |
I. 5 |
|
B. The value of (1129 - 937)(mod 11) |
II. 6 |
|
C. Value of (1129 × 937)(mod 11) |
III. 9 |
|
D. Last digit of (12)12 is |
IV. 3 |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → A - III, B - I, C - IV, D - II
$\text{(A)}\; (1129+937)\mod 11$
$1129\equiv 7,\;\; 937\equiv 2 \Rightarrow 7+2=9 \Rightarrow \text{(III)}$
$\text{(B)}\; (1129-937)\mod 11$
$7-2=5 \Rightarrow \text{(I)}$
$\text{(C)}\; (1129\times 937)\mod 11$
$7\times 2=14\equiv 3 \Rightarrow \text{(IV)}$
$\text{(D)}\; \text{Last digit of } (12)^{12}$
$2^{12}\Rightarrow \text{cycle } 2,4,8,6 \Rightarrow 12\mod 4=0 \Rightarrow 6 \Rightarrow \text{(II)}$
A–III,\; B–I,\; C–IV,\; D–II