Practicing Success
If the solution of the CuSO4 in which copper rod is immersed is diluted to 10 times, the electrode reduction potential (T = 298 K): |
increases by 0.030 V decreases by 0.030 V increases by 0.059 V decreases by 0.0059 V |
decreases by 0.030 V |
\(Cu^{2+} + 2e^− \rightarrow Cu\) \(E_{cell} = E^o_{cell} − \frac{0.0591}{2} log\frac{1}{[Cu^{2+}]}\) The new concentration of \(Cu^{2+}\) is \(\frac{1}{10}\) of \(Cu^{2+}\) \(E^1_{cell} = E^o_{cell} − \frac{0.0591}{2}log\frac{10}{[Cu^{2+}]}\) or, \(E^1_{cell} = E^o_{cell} − \frac{0.0591}{2}log\frac{1}{[Cu^{2+}]} − \frac{0.0591}{2}log 10\) or, \(\Delta E_{cell} = −\frac{0.0591}{2}log10\) or, \(\Delta E_{cell} = −\frac{0.059}{2}\) Thus the electrode potential decreases by \(\frac{0.059 V}{2} = 0.03V\) |