Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Kinetic Theory

Question:

At what temperature will the RMS speed of oxygen molecules become just sufficient for escaping from the Earth's atmosphere? (Given : Mass of oxygen molecule (m) = 2.76 × 10–26 kg Boltzmann's constant kB = 1.38 × 10–23 JK–1)

Options:

2.508 x 104 K

8.360 x 104 K

1.254 x 104 K

5.016 x 104 K

Correct Answer:

8.360 x 104 K

Explanation:

\(V_{escape} = 11200 m/s\)

Let T be the temperature at which it attains velocity \(V_{escape}\)

\(\sqrt{\frac{3 k_B T}{m_{O_{2}}}}\) = 11200 m/s

T = 8.360 x 104 K