Practicing Success
At what temperature will the RMS speed of oxygen molecules become just sufficient for escaping from the Earth's atmosphere? (Given : Mass of oxygen molecule (m) = 2.76 × 10–26 kg Boltzmann's constant kB = 1.38 × 10–23 JK–1) |
2.508 x 104 K 8.360 x 104 K 1.254 x 104 K 5.016 x 104 K |
8.360 x 104 K |
\(V_{escape} = 11200 m/s\) Let T be the temperature at which it attains velocity \(V_{escape}\) \(\sqrt{\frac{3 k_B T}{m_{O_{2}}}}\) = 11200 m/s T = 8.360 x 104 K |