If a + \(\frac{1}{a + 3}\) = 12 Then find , (a + 3)2 + \(\frac{1}{(a + 3)^2}\)

225 222 223 228

223

Given = a + \(\frac{1}{a + 3}\) = 12 By adding 3 on both sides we get, (a + 3) + \(\frac{1}{a + 3}\) = 12 + 3 = 15 (a + 3)2 + \(\frac{1}{(a + 3)^2}\) = 152 - 2 = 223   Note - if x +  \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) =  a2 - 2