Practicing Success
$|ln\, x|\, dx$ equals $(0 < x < 1)$ |
$x + x |ln\, x| + c$ $x |ln\, x| – x + c$ $x + |ln\, x| + c$ $x – |ln\, x | + c$ |
$x + x |ln\, x| + c$ |
$∵ 0 < x < 1\,\, ∴ |ln\, x| = –ln\, x$ Then, $\int\,ln\,x\, dx = – \int\,ln\,.1\,dx$ $= –(x\, ln\, x – x) + c = x + x |ln\, x| + c$ |