CUET Preparation Today
$|ln\, x|\, dx$ equals $(0 < x < 1)$ |
$x - x |ln\, x| + c$ $x |ln\, x| – x + c$ $x + |ln\, x| + c$ $x – |ln\, x | + c$ |
$x - x |ln\, x| + c$ |
$\int |\ln x| \, dx,\quad 0 $\ln x < 0 \Rightarrow |\ln x| = -\ln x$ $= \int -\ln x \, dx$ $= -\left(x \ln x - x\right)$ $= x - x\ln x$ The value is $x - x\ln x + C$. |
