The value of $\int\limits^{1}_{-1}x^2[x]dx$ is :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $-\frac{1}{3}$
$\int\limits^{1}_{-1}x^2[x]dx$
$=+\int\limits^{0}_{-1}x^2[x]dx+\int\limits^{1}_{0}x^2[x]dx$
$=-\int\limits^{0}_{-1}x^2dx+0$
$=\left[-\frac{x^3}{3}\right]^{0}_{-1}=-\frac{1}{3}$