A convex lens made of glass (µ = 1.5) has both radii of curvature 20 cm each. A point object is placed on the principal axis at a distance of 40 cm from the lens. The distance of the image from the lens is: |
10 cm 20 cm 40 cm $\frac{40}{3}$ cm |
40 cm |
The correct answer is Option (3) → 40 cm According to len's Maker formula - $\frac{1}{f}=(μ-1)\left(\frac{1}{R_1}-\frac{1}{R_2}\right)$ $⇒\frac{1}{f}=(1.5-1)\left(\frac{1}{20}-\frac{1}{20}\right)=\frac{1}{20}$ $⇒f=20cm$ On using the lens formula $\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$ $⇒\frac{1}{20}=\frac{1}{v}-\frac{1}{-40}⇒v=40cm$ |