Practicing Success
Practicing Success
CUET Preparation Today
The electric field at the centre of a semi-circular arc of radius 'r', which is charged uniformly and has linear charge density $\lambda$ is: |
$\frac{\lambda}{4 \pi \varepsilon_0 r}$ $\frac{\lambda}{2 \pi \varepsilon_0 r^2}$ $\frac{\lambda^2}{2 \pi \varepsilon_0 r}$ $\frac{\lambda}{2 \pi \varepsilon_0 r}$ |
$\frac{\lambda}{2 \pi \varepsilon_0 r}$ |
The correct answer is Option (4) → $\frac{\lambda}{2 \pi \varepsilon_0 r}$ |
