$x=t^2+t+1, y=t^2-t+1$; then $\frac{d y}{d x}$ is
Answer & explanation
Correct answer: option 2
$x=t^2+t+1, \frac{d x}{d t}=2 t+1, ~~\frac{d y}{d t}=2 t-1$
$\frac{d y}{d x}=\frac{2 t-1}{2 t+1}$
Hence (2) is correct answer.
$x=t^2+t+1, y=t^2-t+1$; then $\frac{d y}{d x}$ is
Correct answer: option 2
$x=t^2+t+1, \frac{d x}{d t}=2 t+1, ~~\frac{d y}{d t}=2 t-1$
$\frac{d y}{d x}=\frac{2 t-1}{2 t+1}$
Hence (2) is correct answer.