If we double the number of turns of coil in a moving coil galvanometer, its voltage sensitivity will:

remain unchanged

The correct answer is Option (2) → remain unchanged

Voltage sensitivity of a moving coil galvanometer is defined as:

$S_v = \frac{V}{I} = I_c R_c / I$ (proportional to the current-to-deflection ratio)

Doubling the number of turns increases both the magnetic torque and the coil resistance proportionally. These two effects cancel each other for voltage sensitivity, leaving it unchanged.

Final Answer: Voltage sensitivity remains the same