Number if ions produced on electrolysis of \([Co(NH_3)_6]Cl_3\) which gives 3 moles of \(AgCl\) on reacting with \(AgNO_3\), are:
Answer & explanation
Correct answer: option 4
The correct answer is option 4. 4.
In this problem, we are to determine the number of ions produced upon electrolysis of \([Co(NH_3)_6]Cl_3\), a coordination complex.
Understanding the Compound:
\([Co(NH_3)_6]Cl_3\) is a coordination complex made up of: A central metal ion \(Co^{3+}\), surrounded by six ammonia ligands \((NH_3)\). These ammonia molecules are neutral ligands and are bound directly to the cobalt ion within the coordination sphere, forming the complex ion \([Co(NH_3)_6]^{3+}\). Three chloride ions \((Cl^-)\) are present outside the coordination sphere. These are not part of the complex but are ionically bound to neutralize the charge of the complex.
Dissociation in Solution:
When \([Co(NH_3)_6]Cl_3\) is dissolved in water, it dissociates into its ions as follows:
\([Co(NH_3)_6]Cl_3 \longrightarrow [Co(NH_3)_6]^{3+} + 3Cl^-\)
One cation: \([Co(NH_3)_6]^{3+}\), which is the complex ion.
Three anions: \(Cl^-\), which are chloride ions.
So, in total, 4 ions are produced when the compound dissociates in solution:
1. The single complex ion \([Co(NH_3)_6]^{3+}\) contributes 1 ion.
2. The three chloride ions \((Cl^-)\) contribute 3 ions.
Reaction with \(AgNO_3\):
When this solution is treated with silver nitrate \((AgNO_3)\), the chloride ions \((Cl^-)\) react with the silver ions \((Ag^+)\) to form a white precipitate of silver chloride \((AgCl)\):
\(Cl^- + Ag^+ \longrightarrow AgCl\)
For every mole of \([Co(NH_3)_6]Cl_3\), 3 moles of chloride ions are available to form 3 moles of \(AgCl\). This confirms that there are 3 chloride ions dissociated from the compound.
Electrolysis:
During electrolysis, the ions in solution participate:
The complex ion \([Co(NH_3)_6]^{3+}\) acts as a cation.
The chloride ions \(Cl^-\) act as anions.
Thus, the total number of ions produced in the solution, which are involved in the electrolysis, is:
1 ion from \([Co(NH_3)_6]^{3+}\)
3 ions from \(3Cl^-\)
Final Conclusion:
The total number of ions produced during the electrolysis of \([Co(NH_3)_6]Cl_3\) is 4.