Van't Hoff factor for $\text{KCl}$ solution assuming the complete dissociation is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 2 ##
van't Hoff factor = final moles / initial moles
$\text{KCl} \rightarrow \text{K}^+ + \text{Cl}^-$
Initial moles = 1; final moles = 2
$\text{van't Hoff factor} = \frac{2}{1} = 2$