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Van't Hoff factor for $\text{KCl}$ solution assuming the complete dissociation is: |
1 2 0.5 1.5 |
2 |
The correct answer is Option (2) → 2 ## van't Hoff factor = final moles / initial moles $\text{KCl} \rightarrow \text{K}^+ + \text{Cl}^-$ Initial moles = 1; final moles = 2 $\text{van't Hoff factor} = \frac{2}{1} = 2$ |
