A resistor develops 200 J of thermal energy in 5 s when a current of 2 A is passed through it. If the current is measured to 5 A, what will be the energy developed in 12 s?

3000 J

The correct answer is Option (2) - 3000 J

$H=I^2Rt$ [Joules law of heating]

where,

H = thermal energy produced

I = current

R = Resistance

t = time

$200=(2)^2R(5)$

$R=\frac{200}{20}=10Ω$

∴ New energy, $H=(5)^2(10)(12)$

$=3000J$