The two ends of a metal rod are maintained at temperatures 100°C and 110°C. The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are maintained at temperatures 200°C and 210°C, the rate of heat flow will be :

4.0 J/s

\(\frac{dQ}{dt}\) ∝ (T₂- T₁)

\(\frac{dQ}{dt} = 4.0 J/s \) 

Since temperature difference is same, rate of flow of heat will remain same.