The magnetic susceptibility of the material of a rod is 499. Permeability of vacuum is $4\pi × 10^{-7} H/m$. The absolute permeability of the material of the rod is |
$4π × 10^{-4} H/m$ $π × 10^{-4} H/m$ $2π × 10^{-4} H/m$ $3π × 10^{-4} H/m$ |
$2π × 10^{-4} H/m$ |
The correct answer is Option (3) → $2π × 10^{-4} H/m$ Given: Magnetic susceptibility, $\chi_m = 499$ Permeability of vacuum, $\mu_0 = 4\pi \times 10^{-7}\ \text{H/m}$ Absolute permeability of the material: $\mu = \mu_0 (1 + \chi_m)$ Substitute values: $\mu = 4\pi \times 10^{-7} (1 + 499) = 4\pi \times 10^{-7} \cdot 500 = 2 \times 10^{-4} \pi\ \text{H/m}$ ∴ Absolute permeability of the material = $2 \pi \times 10^{-4}\ \text{H/m}$ |