CUET Preparation Today
Magnetic field due to the current carrying wire as shown in the figure at point "O" will be:
|
$\frac{\mu_0 I}{2 R}$ $\frac{\mu_0 I}{4 R}$ $\frac{\mu_0 I}{2 \pi R}$ $\frac{\mu_0 I}{4 \pi R}$ |
$\frac{\mu_0 I}{4 R}$ |
The correct answer is Option (2) → $\frac{\mu_0 I}{4 R}$ |
