If the probability distribution of a ran

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Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Probability

Question:

If the probability distribution of a random variable X is

x	1	2	3	4	5
P( X = x)	k	2k	3k	3k	k

Value of P(X > 2) is

Options:

$\frac{5}{6}$

$\frac{9}{10}$

$\frac{4}{5}$

$\frac{7}{10}$

Correct Answer:

$\frac{7}{10}$

Explanation:

Here k + 2k + 3k + 3k + k = 1 $\Rightarrow k=\frac{1}{10}$

so P(X > 2) = 3k + 3k + k = 7k = $\frac{7}{10}$