Practicing Success
Practicing Success
CUET Preparation Today
The value of sin18o is given as $\frac{\sqrt{5}-1}{4}$. Find the value of cosec 18o. |
$\frac{\sqrt{5}+1}{4}$ $\frac{\sqrt{5}+1}{2}$ $\sqrt{5}-1$ $\sqrt{5}+1$ |
$\sqrt{5}+1$ |
sin18º = \(\frac{ √5 - 1}{4}\) { we know, sinθ = \(\frac{1}{cosecθ}\) } cosec 18º = \(\frac{ 4}{√5 - 1}\) = \(\frac{ 4}{√5 - 1}\) × \(\frac{ √5 + 1}{√5 + 1}\) = √5 + 1 |
