PA and PB are two tangents from a point P outside the circle with centre O. If A and B are points on the circle such that ∠APB = 110°, then find the value of ∠OAB?
Answer & explanation
Correct answer: option 2
∠AOB = 180° - 110° = 70°
In ΔOAB
As OA = OB
So ∠OAB = ∠OBA
∠OAB + ∠OBA + ∠AOB = 180°
∠OAB + ∠OBA + 70° = 180°
2∠OAB = 110°
∠OAB = 55°