Practicing Success
Practicing Success
CUET Preparation Today
PA and PB are two tangents from a point P outside the circle with centre O. If A and B are points on the circle such that ∠APB = 110°, then find the value of ∠OAB? |
45° 55° 90° 110° |
55° |
∠AOB = 180° - 110° = 70° In ΔOAB As OA = OB So ∠OAB = ∠OBA ∠OAB + ∠OBA + ∠AOB = 180° ∠OAB + ∠OBA + 70° = 180° 2∠OAB = 110° ∠OAB = 55° |
